6d^2+28d+30=0

Solution for 6d^2+28d+30=0 equation:

6d^2+28d+30=0

a = 6; b = 28; c = +30;
Δ = b2-4ac
Δ = 282-4·6·30
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-8}{2*6}=\frac{-36}{12}
=-3
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+8}{2*6}=\frac{-20}{12}
=-1+2/3
$